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> 计算(1)(-12)-1-23×0.125+(3-27-2012)0(2)(-ab)2÷(2a25b)2•a5b(3)m+2nn-m+nm-n-2nn-m(4)(xx-y-2yx-y)•xyx-2y÷
计算(1)(-12)-1-23×0.125+(3-27-2012)0(2)(-ab)2÷(2a25b)2•a5b(3)m+2nn-m+nm-n-2nn-m(4)(xx-y-2yx-y)•xyx-2y÷
题目简介
计算(1)(-12)-1-23×0.125+(3-27-2012)0(2)(-ab)2÷(2a25b)2•a5b(3)m+2nn-m+nm-n-2nn-m(4)(xx-y-2yx-y)•xyx-2y÷
题目详情
计算
(1)
(-
1
2
)
-1
-
2
3
×0.125+(
3
-27
-2012
)
0
(2)
(
-a
b
)
2
÷(
2
a
2
5b
)
2
•
a
5b
(3)
m+2n
n-m
+
n
m-n
-
2n
n-m
(4)
(
x
x-y
-
2y
x-y
)•
xy
x-2y
÷(
1
x
+
1
y
)
.
题型:解答题
难度:中档
来源:不详
答案
(1)原式=-2+8×0.125+1
=-2+1+1
=0;
(2)原式=
a
2
b
2
÷
4
a
4
25
b
2
•
class="stub"a
5b
=
a
2
b
2
•
25
b
2
4
a
2
•
class="stub"a
5b
=
class="stub"5a
4b
;
(3)原式=
class="stub"m+2n
n-m
-
class="stub"n
n-m
-
class="stub"2n
n-m
=
class="stub"m+2n-n-2n
n-m
=
class="stub"m-n
n-m
=-1;
(4)原式=
class="stub"x-2y
x-y
•
class="stub"xy
x-2y
÷
class="stub"x+y
xy
=
class="stub"x-2y
x-y
•
class="stub"xy
x-2y
•
class="stub"xy
x+y
=
x
2
y
2
x
2
-
y
2
.
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题目简介
计算(1)(-12)-1-23×0.125+(3-27-2012)0(2)(-ab)2÷(2a25b)2•a5b(3)m+2nn-m+nm-n-2nn-m(4)(xx-y-2yx-y)•xyx-2y÷
题目详情
(1)(-
(2)(
(3)
(4)(
答案
=-2+1+1
=0;
(2)原式=
=
=
(3)原式=
=
=
=-1;
(4)原式=
=
=