计算(1)(-12)-1-23×0.125+(3-27-2012)0(2)(-ab)2÷(2a25b)2•a5b(3)m+2nn-m+nm-n-2nn-m(4)(xx-y-2yx-y)•xyx-2y÷

题目简介

计算(1)(-12)-1-23×0.125+(3-27-2012)0(2)(-ab)2÷(2a25b)2•a5b(3)m+2nn-m+nm-n-2nn-m(4)(xx-y-2yx-y)•xyx-2y÷

题目详情

计算
(1)(-
1
2
)-1-23×0.125+(
3-27
-2012)0

(2)(
-a
b
)2÷(
2a2
5b
)2
a
5b

(3)
m+2n
n-m
+
n
m-n
-
2n
n-m

(4)(
x
x-y
-
2y
x-y
)•
xy
x-2y
÷(
1
x
+
1
y
)
题型:解答题难度:中档来源:不详

答案

(1)原式=-2+8×0.125+1
=-2+1+1
=0;

(2)原式=
a2
b2
÷
4a4
25b2
class="stub"a
5b

=
a2
b2
25b2
4a2
class="stub"a
5b

=class="stub"5a
4b


(3)原式=class="stub"m+2n
n-m
-class="stub"n
n-m
-class="stub"2n
n-m

=class="stub"m+2n-n-2n
n-m

=class="stub"m-n
n-m

=-1;

(4)原式=class="stub"x-2y
x-y
class="stub"xy
x-2y
÷class="stub"x+y
xy

=class="stub"x-2y
x-y
class="stub"xy
x-2y
class="stub"xy
x+y

=
x2y2
x2-y2

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