计算:(1)20122-2×2010×2012+20102(2)(-12012)-1+(π-3)0-(-1)2(3)(a+b)(a-b)(a2+b2)(a4+b4)(4)(a-2b-3)(a-2b+3

题目简介

计算:(1)20122-2×2010×2012+20102(2)(-12012)-1+(π-3)0-(-1)2(3)(a+b)(a-b)(a2+b2)(a4+b4)(4)(a-2b-3)(a-2b+3

题目详情

计算:
(1)20122-2×2010×2012+20102
(2)(-
1
2012
)-1+(π-3)0-(-1)2

(3)(a+b)(a-b)(a2+b2)(a4+b4
(4)(a-2b-3)(a-2b+3)
题型:解答题难度:中档来源:不详

答案

(1)原式=2=22=4;
(2)原式=-2012+1-1=-2012;
(3)原式=(a2-b2)(a2+b2)(a4+b4)=(a4-b4)(a4+b4)=a8-b8;
(4)原式=(a-2b)2-9=a2-4ab+4b2-9.

更多内容推荐