计算(1)x2+2xy+y2x2-y2(2)(4x2-4+1x+2)÷1x-2(3)(-12)-2+(119)0+(-5)3÷(-5)2.-数学

题目简介

计算(1)x2+2xy+y2x2-y2(2)(4x2-4+1x+2)÷1x-2(3)(-12)-2+(119)0+(-5)3÷(-5)2.-数学

题目详情

计算
(1)
x2+2xy+y2
x2-y2

(2)(
4
x2-4
+
1
x+2
1
x-2

(3)(-
1
2
)-2+(
1
19
)0+(-5)3÷(-5)2
题型:解答题难度:中档来源:不详

答案

(1)原式=
(x+y)2
(x+y)(x-y)
=class="stub"x+y
x-y


(2)原式=class="stub"4+x-2
(x+2)(x-2)
×(x-2)=class="stub"1
x-2
×(x-2)=1;

(3)原式=4+1-5=0.

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