分式的计算:①aa2-b2-1a+b②b2a-b-a2b-a+a+b③a-2b2(a2b-2)-3④3-x2x-4÷(x+2-5x-2)⑤3b-aa2-b2-a+2ba-b⑥(12a)-2b2(2a2

题目简介

分式的计算:①aa2-b2-1a+b②b2a-b-a2b-a+a+b③a-2b2(a2b-2)-3④3-x2x-4÷(x+2-5x-2)⑤3b-aa2-b2-a+2ba-b⑥(12a)-2b2(2a2

题目详情

分式的计算:
a
a2-b2
-
1
a+b

b2
a-b
-
a2
b-a
+a+b

③a-2b2(a2b-2-3
3-x
2x-4
÷(x+2-
5
x-2
)

3b-a
a2-b2
-
a+2b
a-b

(
1
2
a)-2b2(2a2b-2)-1
题型:解答题难度:中档来源:不详

答案

①原式=class="stub"a
(a+b)(a-b)
-class="stub"a-b
(a+b)(a-b)

=
a-(a-b)
(a+b)(a-b)

=class="stub"b
(a+b)(a-b)


②原式=
b2
a-b
+
a2
a-b
+
(a+b)(a-b)
a-b

=
a2+b2+(a2-b2)
a-b

=
2a2
a-b


③原式=a-2 b2•a-6 b6
=a-8 b8;

④原式=class="stub"3-x
2(x-2)
÷[
(x+2)(x-2)
x-2
-class="stub"5
x-2
]
=class="stub"3-x
2(x-2)
÷
x2-4-5
x-2

=class="stub"3-x
2(x-2)
÷
(x+3)(x-3)
x-2

=class="stub"3-x
2(x-2)
2(x-2)
(x+3)(x-3)
=-class="stub"1
x+3


⑤原式=class="stub"3b-a
(a+b)(a-b)
-
(a+2b)(a+b)
(a+b)(a-b)

=
3b-a-(a2+ab+2ab+2b2)
(a+b)(a-b)

=
3b-a-a2+3ab-2b2
(a+b)(a-b)


⑥原式=4a-2 b2•class="stub"1
2
a-2 b2
=2a-4 b4
=
2b4
a4

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