计算题:(1)(-12)2+14-(-1)2008+(π-3)0(2)(a+b)2-2a(b+1)-a2b÷b(3)5ab2-{2a2b-[3a2b-ab(b-2a)(4)解方程:(x-2)2-4=0

题目简介

计算题:(1)(-12)2+14-(-1)2008+(π-3)0(2)(a+b)2-2a(b+1)-a2b÷b(3)5ab2-{2a2b-[3a2b-ab(b-2a)(4)解方程:(x-2)2-4=0

题目详情

计算题:
(1)(-
1
2
)2+
1
4
-(-1)2008+(π-3)0

(2)(a+b)2-2a(b+1)-a2b÷b
(3)5ab2-{2a2b-[3a2b-ab(b-2a)
(4)解方程:(x-2)2-4=0.
题型:解答题难度:中档来源:不详

答案

(1)原式=class="stub"1
4
+class="stub"1
2
-1+1
=class="stub"3
4


(2)原式=a2+2ab+b2-2ab-2a-a2
=b2-2a;

(3)原式=5ab2-{[2a2b-(3a2b-(ab2-2a2b)÷(-class="stub"1
2
ab)}
=5ab2-[2a2b-(3a2b+2b-4a)]
=5ab2-(2a2b-3a2b-2b+4a)
=5ab2-2a2b+3a2b+2b-4a
=5ab2+a2b+2b-4a;

(4)(x-2)2-4=0,
变形得:(x-2)2=4,
开方得:x-2=2或x-2=-2,
解得:x1=4,x2=0.

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