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> 计算题:(1)(-12)2+14-(-1)2008+(π-3)0(2)(a+b)2-2a(b+1)-a2b÷b(3)5ab2-{2a2b-[3a2b-ab(b-2a)(4)解方程:(x-2)2-4=0
计算题:(1)(-12)2+14-(-1)2008+(π-3)0(2)(a+b)2-2a(b+1)-a2b÷b(3)5ab2-{2a2b-[3a2b-ab(b-2a)(4)解方程:(x-2)2-4=0
题目简介
计算题:(1)(-12)2+14-(-1)2008+(π-3)0(2)(a+b)2-2a(b+1)-a2b÷b(3)5ab2-{2a2b-[3a2b-ab(b-2a)(4)解方程:(x-2)2-4=0
题目详情
计算题:
(1)
(-
1
2
)
2
+
1
4
-(-1
)
2008
+(π-3
)
0
(2)(a+b)
2
-2a(b+1)-a
2
b÷b
(3)
5a
b
2
-{2
a
2
b-[3
a
2
b-ab(b-2a)
(4)解方程:(x-2)
2
-4=0.
题型:解答题
难度:中档
来源:不详
答案
(1)原式=
class="stub"1
4
+
class="stub"1
2
-1+1
=
class="stub"3
4
;
(2)原式=a2+2ab+b2-2ab-2a-a2
=b2-2a;
(3)原式=5ab2-{[2a2b-(3a2b-(ab2-2a2b)÷(-
class="stub"1
2
ab)}
=5ab2-[2a2b-(3a2b+2b-4a)]
=5ab2-(2a2b-3a2b-2b+4a)
=5ab2-2a2b+3a2b+2b-4a
=5ab2+a2b+2b-4a;
(4)(x-2)2-4=0,
变形得:(x-2)2=4,
开方得:x-2=2或x-2=-2,
解得:x1=4,x2=0.
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题目简介
计算题:(1)(-12)2+14-(-1)2008+(π-3)0(2)(a+b)2-2a(b+1)-a2b÷b(3)5ab2-{2a2b-[3a2b-ab(b-2a)(4)解方程:(x-2)2-4=0
题目详情
(1)(-
(2)(a+b)2-2a(b+1)-a2b÷b
(3)5ab2-{2a2b-[3a2b-ab(b-2a)
(4)解方程:(x-2)2-4=0.
答案
=
(2)原式=a2+2ab+b2-2ab-2a-a2
=b2-2a;
(3)原式=5ab2-{[2a2b-(3a2b-(ab2-2a2b)÷(-
=5ab2-[2a2b-(3a2b+2b-4a)]
=5ab2-(2a2b-3a2b-2b+4a)
=5ab2-2a2b+3a2b+2b-4a
=5ab2+a2b+2b-4a;
(4)(x-2)2-4=0,
变形得:(x-2)2=4,
开方得:x-2=2或x-2=-2,
解得:x1=4,x2=0.