递等式计算:1.8×[6512÷16+38×(9-2712)]÷2341223÷0.8-[623+1718×(234-2.15)].-数学

题目简介

递等式计算:1.8×[6512÷16+38×(9-2712)]÷2341223÷0.8-[623+1718×(234-2.15)].-数学

题目详情

递等式计算:
1.8×[6
5
12
÷16+
3
8
×(9-2
7
12
)]÷2
3
4

12
2
3
÷0.8-[6
2
3
+1
7
18
×(2
3
4
-2.15)].
题型:解答题难度:中档来源:不详

答案

(1)1.8×[6class="stub"5
12
÷16+class="stub"3
8
×(9-2class="stub"7
12
)]÷2class="stub"3
4

=1.8×[6class="stub"5
12
÷16+class="stub"3
8
×class="stub"77
12
]÷2class="stub"3
4

=1.8×[class="stub"77
12
×class="stub"1
16
+class="stub"3
8
×class="stub"77
12
]÷2class="stub"3
4

=1.8×[(class="stub"1
16
+class="stub"3
8
)×class="stub"77
12
]÷2class="stub"3
4

=1.8×[class="stub"7
16
×class="stub"77
12
]÷2class="stub"3
4

=class="stub"9
5
×class="stub"7
16
×class="stub"77
12
×class="stub"4
11

=class="stub"147
80


(2)12class="stub"2
3
÷0.8-[6class="stub"2
3
+1class="stub"7
18
×(2class="stub"3
4
-2.15)],
=12class="stub"2
3
÷0.8-[6class="stub"2
3
+1class="stub"7
18
×class="stub"3
5
],
=12class="stub"2
3
÷0.8-[6class="stub"2
3
+class="stub"5
6
],
=12class="stub"2
3
÷0.8-class="stub"45
6

=class="stub"95
6
-class="stub"45
6

=class="stub"25
3

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