(1)计算:22-1-8-(2+1)0.(2)|-12|+sin30°+2cos245°-13tan260°.-数学

题目简介

(1)计算:22-1-8-(2+1)0.(2)|-12|+sin30°+2cos245°-13tan260°.-数学

题目详情

(1)计算:
2
2
-1
-
8
-(
2
+1)0

(2)|-
1
2
|+sin30°+2cos245°-
1
3
tan260°
题型:解答题难度:中档来源:不详

答案

(1)原式=
2(
2
+1)
2-1
-2
2
-1,
=2
2
+2-2
2
-1,
=1;
(2)原式=class="stub"1
2
+class="stub"1
2
+2×(
2
2
)
2
-class="stub"1
3
×(
3
)
2

=class="stub"1
2
+class="stub"1
2
+1-1,
=1.

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