计算:(13)-1+16÷(-2)3+(2011-π3)0-3•tan60°.-数学

题目简介

计算:(13)-1+16÷(-2)3+(2011-π3)0-3•tan60°.-数学

题目详情

计算:(
1
3
)-1+16÷(-2)3+(2011-
π
3
)0-
3
•tan60°
题型:解答题难度:中档来源:不详

答案

(class="stub"1
3
)
-1
+16÷(-2)3+(2011-class="stub"π
3
)
0
-
3
•tan60°

=class="stub"1
class="stub"1
3
+16÷(-8)+1-
3
×
3

=3-2+1-3
=-1.

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