计算:(1)-32-23÷13×3;(2)(1-16+34)×(-48);(3)13m-32n-56n-16m;(4)先化简,再求值:(2x3-xyz)-2(x3-y3+xyz)+(xyz-2y3),

题目简介

计算:(1)-32-23÷13×3;(2)(1-16+34)×(-48);(3)13m-32n-56n-16m;(4)先化简,再求值:(2x3-xyz)-2(x3-y3+xyz)+(xyz-2y3),

题目详情

计算:
(1)-32-23÷
1
3
×3;
(2)(1-
1
6
+
3
4
)×(-48);
(3)
1
3
m-
3
2
n-
5
6
n-
1
6
m

(4)先化简,再求值:(2x3-xyz)-2(x3-y3+xyz)+(xyz-2y3),其中x=1,y=2,z=-3.
题型:解答题难度:中档来源:不详

答案


(1)-32-23÷class="stub"1
3
×3=-9-8×3×3=-81;
(2)(1-class="stub"1
6
+class="stub"3
4
)×(-48)=1×(-48)-class="stub"1
6
×(-48)+class="stub"3
4
×(-48)=-48+8-36=-76;
(3)原式=(class="stub"1
3
-class="stub"1
6
)m+(-class="stub"3
2
-class="stub"5
6
)n=class="stub"m
6
-class="stub"7
3
n

(4)原式=2x3-xyz-2x3+2y3-2xyz+xyz-2y3=-2xyz,
当x=1,y=2,z=-3时,原式=-2×1×2×(-3)=12.

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