用递等式计算.38+(45-14)58+67+(38-67)14-(14-213)715+619+815.-数学

题目简介

用递等式计算.38+(45-14)58+67+(38-67)14-(14-213)715+619+815.-数学

题目详情

用递等式计算.
3
8
+(
4
5
-
1
4
5
8
+
6
7
+(
3
8
-
6
7
1
4
-(
1
4
-
2
13
7
15
+
6
19
+
8
15
题型:解答题难度:中档来源:不详

答案

(1)class="stub"3
8
+(class="stub"4
5
-class="stub"1
4
),
=class="stub"3
8
+class="stub"11
20

=class="stub"37
40


(2)class="stub"5
8
+class="stub"6
7
+(class="stub"3
8
-class="stub"6
7
),
=class="stub"5
8
+class="stub"6
7
+class="stub"3
8
-class="stub"6
7

=(class="stub"5
8
+class="stub"3
8
)+(class="stub"6
7
-class="stub"6
7
),
=1-0,
=1;

(3)class="stub"1
4
-(class="stub"1
4
-class="stub"2
13
),
=class="stub"1
4
-class="stub"1
4
+class="stub"2
13

=0+class="stub"2
13

=class="stub"2
13


(4)class="stub"7
15
+class="stub"6
19
+class="stub"8
15

=class="stub"7
15
+class="stub"8
15
+class="stub"6
19

=1+class="stub"6
19

=1class="stub"6
19

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