已知x2-xy=21,xy-y2=-12,分别求式子x2-y2与x2-2xy+y2的值.-数学

题目简介

已知x2-xy=21,xy-y2=-12,分别求式子x2-y2与x2-2xy+y2的值.-数学

题目详情

已知x2-xy=21,xy-y2=-12,分别求式子x2-y2与x2-2xy+y2的值.
题型:解答题难度:中档来源:不详

答案

x2-y2=(x2-xy)+(xy-y2)=21-12=9;
x2-2xy+y2=(x2-xy)-(xy-y2)=21+12=33.

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