计算(1)a2-a4+(-a2)3(2)(-3ab)-(-a2c)-(6ab2c)(3)(-14)-1+(-2)2×50-(12)-2(4)[(a5)4÷a12]-a4.-数学

题目简介

计算(1)a2-a4+(-a2)3(2)(-3ab)-(-a2c)-(6ab2c)(3)(-14)-1+(-2)2×50-(12)-2(4)[(a5)4÷a12]-a4.-数学

题目详情

计算
(1)a2-a4+(-a23
(2)(-3ab)-(-a2c)-(6ab2c)
(3)(-
1
4
)-1+(-2)2×50-(
1
2
)-2

(4)[(a54÷a12]-a4
题型:解答题难度:中档来源:不详

答案

(1)a2•a4+(-a2)3
=a6-a6
=0;

(2)(-3ab)•(-a2c)•(6ab2c)
=[-3×(-1)×6](a•a2•a)(b•b2)(c•c)
=18a4b3c2;

(3)(-class="stub"1
4
)-1+(-2)2×50-(class="stub"1
2
)-2

=-4+4×1-4
=-4+4-4
=-4;

(4)[(a5)4÷a12]•a4
=[a20÷a12]•a4
=a8•a4.
=a12.

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