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> 计算(1)a2-a4+(-a2)3(2)(-3ab)-(-a2c)-(6ab2c)(3)(-14)-1+(-2)2×50-(12)-2(4)[(a5)4÷a12]-a4.-数学
计算(1)a2-a4+(-a2)3(2)(-3ab)-(-a2c)-(6ab2c)(3)(-14)-1+(-2)2×50-(12)-2(4)[(a5)4÷a12]-a4.-数学
题目简介
计算(1)a2-a4+(-a2)3(2)(-3ab)-(-a2c)-(6ab2c)(3)(-14)-1+(-2)2×50-(12)-2(4)[(a5)4÷a12]-a4.-数学
题目详情
计算
(1)a
2
-a
4
+(-a
2
)
3
(2)(-3ab)-(-a
2
c)-(6ab
2
c)
(3)
(-
1
4
)
-1
+(-2
)
2
×
5
0
-(
1
2
)
-2
(4)[(a
5
)
4
÷a
12
]-a
4
.
题型:解答题
难度:中档
来源:不详
答案
(1)a2•a4+(-a2)3
=a6-a6
=0;
(2)(-3ab)•(-a2c)•(6ab2c)
=[-3×(-1)×6](a•a2•a)(b•b2)(c•c)
=18a4b3c2;
(3)
(-
class="stub"1
4
)
-1
+(-2
)
2
×
5
0
-(
class="stub"1
2
)
-2
=-4+4×1-4
=-4+4-4
=-4;
(4)[(a5)4÷a12]•a4
=[a20÷a12]•a4
=a8•a4.
=a12.
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题目简介
计算(1)a2-a4+(-a2)3(2)(-3ab)-(-a2c)-(6ab2c)(3)(-14)-1+(-2)2×50-(12)-2(4)[(a5)4÷a12]-a4.-数学
题目详情
(1)a2-a4+(-a2)3
(2)(-3ab)-(-a2c)-(6ab2c)
(3)(-
(4)[(a5)4÷a12]-a4.
答案
=a6-a6
=0;
(2)(-3ab)•(-a2c)•(6ab2c)
=[-3×(-1)×6](a•a2•a)(b•b2)(c•c)
=18a4b3c2;
(3)(-
=-4+4×1-4
=-4+4-4
=-4;
(4)[(a5)4÷a12]•a4
=[a20÷a12]•a4
=a8•a4.
=a12.