(1)计算:-32-(-12)-3-|1-3|+27.(2)先化简,再求值:(1x2-2x-1x2-4x+4)÷2x2-2x,其中x=1.-数学

题目简介

(1)计算:-32-(-12)-3-|1-3|+27.(2)先化简,再求值:(1x2-2x-1x2-4x+4)÷2x2-2x,其中x=1.-数学

题目详情

(1)计算:-32-(-
1
2
)-3-|1-
3
|+
27

(2)先化简,再求值:(
1
x2-2x
-
1
x2-4x+4
)÷
2
x2-2x
,其中x=1.
题型:解答题难度:中档来源:不详

答案

(1)原式=-9-(-8)+1-
3
+3
3

=2
3


(2)原式=[class="stub"1
x(x-2)
-class="stub"1
(x-2)2
x(x-2)
2

=class="stub"1
x(x-2)
×
x(x-2)
2
-class="stub"1
(x-2)2
×
x(x-2)
2

=class="stub"1
2
-class="stub"x
2(x-2)

=class="stub"x-2-x
2(x-2)
=class="stub"1
2-x

当x=1时,原式=class="stub"1
2-1
=1.

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