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> 先化简,再求值:(1a-b+1b+a)÷aba+b,其中a=2+1,b=2.-数学
先化简,再求值:(1a-b+1b+a)÷aba+b,其中a=2+1,b=2.-数学
题目简介
先化简,再求值:(1a-b+1b+a)÷aba+b,其中a=2+1,b=2.-数学
题目详情
先化简,再求值:
(
1
a-b
+
1
b+a
)÷
ab
a+b
,其中a=
2
+1,b=
2
.
题型:解答题
难度:中档
来源:黄石
答案
原式=
(b+a)+(a-b)
(a-b)(b+a)
•
class="stub"a+b
ab
=
class="stub"2
(a-b)b
,
∵
a=
2
+1,b=
2
∴
原式=
class="stub"2
(
2
+1-
2
)
2
=
class="stub"2
2
=
2
.
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题目简介
先化简,再求值:(1a-b+1b+a)÷aba+b,其中a=2+1,b=2.-数学
题目详情
答案
=
∵a=
∴原式=