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> (1)计算:(-2)2-4+(13)-1-12sin30°(2)解方程:x-1x+1+2x1-2x=0.-数学
(1)计算:(-2)2-4+(13)-1-12sin30°(2)解方程:x-1x+1+2x1-2x=0.-数学
题目简介
(1)计算:(-2)2-4+(13)-1-12sin30°(2)解方程:x-1x+1+2x1-2x=0.-数学
题目详情
(1)计算:
(-2
)
2
-
4
+(
1
3
)
-1
-
1
2
sin30°
(2)解方程:
x-1
x+1
+
2x
1-2x
=0
.
题型:解答题
难度:中档
来源:盐城模拟
答案
(1)(-2)2-
4
+(
class="stub"1
3
)-1-
class="stub"1
2
sin30°,
=4-2+3-
class="stub"1
2
×
class="stub"1
2
,
=5-
class="stub"1
4
,
=
class="stub"19
4
;
(2)方程两边都乘以(x+1)(1-2x)得,
(x-1)(1-2x)+2x(x+1)=0,
整理得,5x=1,
解得x=
class="stub"1
5
,
检验:当x=
class="stub"1
5
时,(x+1)(1-2x)=(
class="stub"1
5
+1)(1-2×
class="stub"1
5
)=
class="stub"18
25
≠0,
所以,原分式方程的解是x=
class="stub"1
5
.
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题目简介
(1)计算:(-2)2-4+(13)-1-12sin30°(2)解方程:x-1x+1+2x1-2x=0.-数学
题目详情
(2)解方程:
答案
=4-2+3-
=5-
=
(2)方程两边都乘以(x+1)(1-2x)得,
(x-1)(1-2x)+2x(x+1)=0,
整理得,5x=1,
解得x=
检验:当x=
所以,原分式方程的解是x=