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> 计算:(1)2-1-tan60°+(5-1)0+|-3|;(2)先化简再求值:a-1a+2•a2-4a2-2a+1÷1a2-1,其中a满足a2-a=0.-数学
计算:(1)2-1-tan60°+(5-1)0+|-3|;(2)先化简再求值:a-1a+2•a2-4a2-2a+1÷1a2-1,其中a满足a2-a=0.-数学
题目简介
计算:(1)2-1-tan60°+(5-1)0+|-3|;(2)先化简再求值:a-1a+2•a2-4a2-2a+1÷1a2-1,其中a满足a2-a=0.-数学
题目详情
计算:
(1)
2
-1
-tan60°+(
5
-1
)
0
+|-
3
|
;
(2)先化简再求值:
a-1
a+2
•
a
2
-4
a
2
-2a+1
÷
1
a
2
-1
,其中a满足a
2
-a=0.
题型:解答题
难度:中档
来源:不详
答案
(1)原式=
class="stub"1
2
-
3
+1+
3
=
class="stub"3
2
;
(2)原式=
class="stub"a-1
a+2
•
(a+2)(a-2)
(a-1
)
2
•(a+1)(a-1)=(a-2)(a+1)=a2-a-2,
当a2-a=0时,原式=0-2=-2.
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题目简介
计算:(1)2-1-tan60°+(5-1)0+|-3|;(2)先化简再求值:a-1a+2•a2-4a2-2a+1÷1a2-1,其中a满足a2-a=0.-数学
题目详情
(1)2-1-tan60°+(
(2)先化简再求值:
答案
(2)原式=
当a2-a=0时,原式=0-2=-2.