121+12+13(1+12)(1+13)+14(1+12)(1+13)(1+14)+…+11999(1+12)(1+13)…(1+11999).-数学

题目简介

121+12+13(1+12)(1+13)+14(1+12)(1+13)(1+14)+…+11999(1+12)(1+13)…(1+11999).-数学

题目详情

1
2
1+
1
2
+
1
3
(1+
1
2
)(1+
1
3
)
+
1
4
(1+
1
2
)(1+
1
3
)(1+
1
4
)
+…+
1
1999
(1+
1
2
)(1+
1
3
)…(1+
1
1999
)
题型:解答题难度:中档来源:不详

答案

原式=
class="stub"1
2
×4
(1+class="stub"1
2
)×4
+
class="stub"1
3
×6
class="stub"3
2
×class="stub"4
3
×6
+…+
class="stub"1
1999
×1999×2
class="stub"3
2
×class="stub"4
3
×…×class="stub"2000
1999
×1999×2

=class="stub"2
2×3
+class="stub"2
3×4
+…+class="stub"2
1999×2000

=(class="stub"1
2
-class="stub"1
3
+class="stub"1
3
-class="stub"1
4
+…+class="stub"1
1999
-class="stub"1
2000
)×2,
=(class="stub"1
2
-class="stub"1
2000
)×2,
=1-class="stub"1
1000

=class="stub"999
1000

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