(1)计算:412-(32-18);(2)计算:(a3b-ab+2ba+ab)÷ba.-数学

题目简介

(1)计算:412-(32-18);(2)计算:(a3b-ab+2ba+ab)÷ba.-数学

题目详情

(1)计算:4
1
2
-(
32
-
18
);
(2)计算:(
a3b
-
a
b
+2
b
a
+
ab
)÷
b
a
题型:解答题难度:中档来源:不详

答案

(1)原式=2
2
-4
2
+3
2
=0;
(2)原式=
a4
-
a2
b2
+2+
a2

=a2+a-class="stub"a
b
+2.

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