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> (1)(12)-2-4sin30°+(π-2)0;(2)化简:(4x2-4+1x+2)÷1x-2.-数学
(1)(12)-2-4sin30°+(π-2)0;(2)化简:(4x2-4+1x+2)÷1x-2.-数学
题目简介
(1)(12)-2-4sin30°+(π-2)0;(2)化简:(4x2-4+1x+2)÷1x-2.-数学
题目详情
(1)
(
1
2
)
-2
-4sin30°
+(π-2)
0
;
(2)化简:
(
4
x
2
-4
+
1
x+2
)÷
1
x-2
.
题型:解答题
难度:中档
来源:鼓楼区二模
答案
(1)原式=4-2+1,
=3;
(2)原式=
(
class="stub"4
(x+2)(x-2)
+
class="stub"x-2
(x+2)(x-2)
)÷
class="stub"1
x-2
,(2分)
=
class="stub"x+2
(x+2)(x-2)
•(x-2)
,(3分)
=1.(4分)
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若(x-4)0+x-2有意义,则x的取值范
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题目简介
(1)(12)-2-4sin30°+(π-2)0;(2)化简:(4x2-4+1x+2)÷1x-2.-数学
题目详情
(2)化简:(
答案
=3;
(2)原式=(
=
=1.(4分)