用递等式计算.(1)(3618÷18-145)×20(2)16.8-45÷0.9×0.16(3)49×320+1115÷22(4)96÷[(56-34)×2.4+35].-数学

题目简介

用递等式计算.(1)(3618÷18-145)×20(2)16.8-45÷0.9×0.16(3)49×320+1115÷22(4)96÷[(56-34)×2.4+35].-数学

题目详情

用递等式计算.
(1)(3618÷18-145)×20
(2)16.8-45÷0.9×0.16
(3)
4
9
×
3
20
+
11
15
÷22
(4)96÷[(
5
6
-
3
4
)×2.4+
3
5
].
题型:解答题难度:中档来源:不详

答案

(1)(3618÷18-145)×20,
=(201-145)×20,
=56×20,
=1120

(2)16.8-45÷0.9×0.16,
=16.8-50×0.16,
=16.8-8,
=8.8;

(3)class="stub"4
9
×class="stub"3
20
+class="stub"11
15
÷22,
=class="stub"1
15
+class="stub"11
15
÷22,
=class="stub"1
15
+class="stub"1
30

=class="stub"1
10


(4)96÷[(class="stub"5
6
-class="stub"3
4
)×2.4+class="stub"3
5
],
=96÷[class="stub"1
12
×2.4+class="stub"3
5
],
=96÷[class="stub"1
5
+class="stub"3
5
],
=96÷class="stub"4
5

=120.

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