用递等式计算.(1)2180+540÷18×24(2)157×(5÷56-56÷5)(3)415÷[2.5-0.4×(245-1.05)](4)[1-(413-1.75×2)]÷212.-数学

题目简介

用递等式计算.(1)2180+540÷18×24(2)157×(5÷56-56÷5)(3)415÷[2.5-0.4×(245-1.05)](4)[1-(413-1.75×2)]÷212.-数学

题目详情

用递等式计算.
(1)2180+540÷18×24
(2)1
5
7
×(5÷
5
6
-
5
6
÷5)
(3)4
1
5
÷[2.5-0.4×(2
4
5
-1.05)]
(4)[1-(4
1
3
-1.75×2)]÷2
1
2
题型:解答题难度:中档来源:不详

答案

(1)2180+540÷18×24,
=2180+30×24,
=2180-720,
=1460;

(2)1class="stub"5
7
×( 5÷class="stub"5
6
-class="stub"5
6
÷5 ),
=1class="stub"5
7
×( 6-class="stub"5
6
÷5 ),
=1class="stub"5
7
×( 6-class="stub"1
6
),
=class="stub"12
7
×class="stub"35
6

=10;

(3)4class="stub"1
5
÷[2.5-0.4×(2class="stub"4
5
-1.05)],
=4class="stub"1
5
÷[2.5-0.4×1.75],
=4class="stub"1
5
÷[2.5-0.7],
=4class="stub"1
5
÷1.8,
=class="stub"21
5
×class="stub"5
9

=class="stub"7
3


(4)[1-(4class="stub"1
3
-1.75×2)]÷2class="stub"1
2

=[1-(4class="stub"1
3
-3.5)]÷2class="stub"1
2

=[1-class="stub"5
6
2class="stub"1
2

=class="stub"1
6
×class="stub"2
5

=class="stub"1
15

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