(1)计算:(1-13)0+(-3)-1+(-112)2011(23)2012;(2)先化简,再求值:[(2xy+3)(2xy-3)+(xy+3)2]÷xy,其中x=15,y=-2.-数学

题目简介

(1)计算:(1-13)0+(-3)-1+(-112)2011(23)2012;(2)先化简,再求值:[(2xy+3)(2xy-3)+(xy+3)2]÷xy,其中x=15,y=-2.-数学

题目详情

(1)计算:(1-
1
3
)0+(-3)-1+(-1
1
2
)2011(
2
3
)2012

(2)先化简,再求值:[(2xy+3)(2xy-3)+(xy+3)2]÷xy,其中x=
1
5
,y=-2.
题型:解答题难度:中档来源:不详

答案

(1)原式=1-class="stub"1
3
+(-class="stub"3
2
×class="stub"2
3
)2011×class="stub"2
3
=1-class="stub"1
3
-class="stub"2
3
=0;
(2)原式=(4x2y2-9+x2y2+6xy+9)÷xy=(5x2y2+6xy)÷xy=5xy+6,
当x=class="stub"1
5
,y=-2时,原式=5×class="stub"1
5
×(-2)+6=-2+6=4.

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