计算:(1)|-1|-2+(π-3)0-2-2;(2)[(x-y)2-(x-y)2]÷(-2xy)-数学

题目简介

计算:(1)|-1|-2+(π-3)0-2-2;(2)[(x-y)2-(x-y)2]÷(-2xy)-数学

题目详情

计算:
(1)|-1|-2+(π-3)0-2-2
(2)[(x-y)2-(x-y)2]÷(-2xy)
题型:解答题难度:中档来源:不详

答案

(1)原式=1-2+1-class="stub"1
4
=-class="stub"1
4

(2)原式=(x2-2xy+y2-x2+2xy-y2)÷(-2xy)=0.

更多内容推荐