解方程(1)(x+3)2=(1-2x)2(2)3x(x-1)=2-2x(3)(13)-1-|-2+3tan45°|+(2-1.41)0(4)4sin30°+23cos30°+tan45°.-数学

题目简介

解方程(1)(x+3)2=(1-2x)2(2)3x(x-1)=2-2x(3)(13)-1-|-2+3tan45°|+(2-1.41)0(4)4sin30°+23cos30°+tan45°.-数学

题目详情

解方程
(1)(x+3)2=(1-2x)2
(2)3x(x-1)=2-2x
(3)(
1
3
)-1-|-2+
3
tan45°|+(
2
-1.41)0

(4)4sin30°+2
3
cos30°+tan45°
题型:解答题难度:中档来源:不详

答案

(1)∵x+3=±(1-2x),
∴x1=-class="stub"2
3
,x2=-4;

(2)∵3x(x-1)+2(x-1)=0,
∴(x-1)(3x+2)=0,
∴x-1=0或3x+2=0,
∴x1=1,x2=-class="stub"2
3


(3)原式=3-|-2+
3
×1|+2
=3-(2-
3
)+2
=3-2+
3
+2
=3+
3


(4)原式=4×class="stub"1
2
+2
3
×
3
2
+1
=2+3+1
=6.

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