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> 解答下列各题:(1)计算:(48+20)-(12-5);(2)解方程:x2-2x-4=0;(3)解方程:3(x-5)2=2(5-x);(4)计算:3tan230°+2(sin45°-1)2.-数学
解答下列各题:(1)计算:(48+20)-(12-5);(2)解方程:x2-2x-4=0;(3)解方程:3(x-5)2=2(5-x);(4)计算:3tan230°+2(sin45°-1)2.-数学
题目简介
解答下列各题:(1)计算:(48+20)-(12-5);(2)解方程:x2-2x-4=0;(3)解方程:3(x-5)2=2(5-x);(4)计算:3tan230°+2(sin45°-1)2.-数学
题目详情
解答下列各题:(1)计算:(
48
+
20
)-(
12
-
5
);
(2)解方程:x
2
-2x-4=0;
(3)解方程:3(x-5)
2
=2(5-x);
(4)计算:3tan
2
30°+2
(sin45°-1)
2
.
题型:解答题
难度:中档
来源:不详
答案
(1)(
48
+
20
)-(
12
-
5
)
=(4
3
+2
5
)-(2
3
-
5
)
=4
3
+2
5
-2
3
+
5
=2
3
+3
5
;
(2)移项,得x2-2x=4
配方x2-2x+1=4+1
(x-1)2=5
由此可得x-1=±
5
∴x1=1+
5
,x2=1-
5
;
(3)原式=3(x-5)2+2(x-5)=0
即3(x-5)+2=0
3x-15+2=0
x=
15±
15
2
-4×3×2
6
∴x1=5,x2=
class="stub"13
3
;
(4)原式=3×(
3
3
)2+2|
2
2
-1|
=3×
class="stub"1
3
+2(1-
2
2
)
=1+2-
2
=3-
2
.
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下列计算正确的是()A.2+3=5B.3-2=1
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题目简介
解答下列各题:(1)计算:(48+20)-(12-5);(2)解方程:x2-2x-4=0;(3)解方程:3(x-5)2=2(5-x);(4)计算:3tan230°+2(sin45°-1)2.-数学
题目详情
(2)解方程:x2-2x-4=0;
(3)解方程:3(x-5)2=2(5-x);
(4)计算:3tan230°+2
答案
=(4
=4
=2
(2)移项,得x2-2x=4
配方x2-2x+1=4+1
(x-1)2=5
由此可得x-1=±
∴x1=1+
(3)原式=3(x-5)2+2(x-5)=0
即3(x-5)+2=0
3x-15+2=0
x=
∴x1=5,x2=
(4)原式=3×(
=3×
=1+2-
=3-