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> 计算:(1)2x+1-1x-1;(2)0.25×(-2)-2÷(16)-1-(π-3)0.-数学
计算:(1)2x+1-1x-1;(2)0.25×(-2)-2÷(16)-1-(π-3)0.-数学
题目简介
计算:(1)2x+1-1x-1;(2)0.25×(-2)-2÷(16)-1-(π-3)0.-数学
题目详情
计算:
(1)
2
x+1
-
1
x-1
;
(2) 0.25×(-2)
-2
÷(16)
-1
-(π-3)
0
.
题型:解答题
难度:中档
来源:不详
答案
(1)
class="stub"2
x+1
-
class="stub"1
x-1
=
class="stub"2x-2-x-1
(x+1)(x-1)
=
class="stub"x-3
x
2
-1
,
(2)0.25×(-2)-2÷(16)-1-(π-3)0=
class="stub"1
4
×
class="stub"1
4
×16-1=0.
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(1)解方程:1-x2-x-3=1x-2;(2)计算0.2
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题目简介
计算:(1)2x+1-1x-1;(2)0.25×(-2)-2÷(16)-1-(π-3)0.-数学
题目详情
(1)
(2) 0.25×(-2)-2÷(16)-1-(π-3)0.
答案
(2)0.25×(-2)-2÷(16)-1-(π-3)0=