(1)解方程:1-x2-x-3=1x-2;(2)计算0.25×(-2)-2÷(16)-1-(π-3)0;(3)先化简(x+1x-1+1x2-2x+1)÷xx-1,然后选取一个你喜欢的x的值代入计算.-

题目简介

(1)解方程:1-x2-x-3=1x-2;(2)计算0.25×(-2)-2÷(16)-1-(π-3)0;(3)先化简(x+1x-1+1x2-2x+1)÷xx-1,然后选取一个你喜欢的x的值代入计算.-

题目详情

(1)解方程:
1-x
2-x
-3=
1
x-2

(2)计算0.25×(-2)-2÷(16)-1-(π-3)0
(3)先化简(
x+1
x-1
+
1
x2-2x+1
x
x-1
,然后选取一个你喜欢的x的值代入计算.
题型:解答题难度:中档来源:不详

答案

(1)方程两边同乘(x-2),
得:x-1-3(x-2)=1,
整理解得x=2.
经检验,x=2是原方程的增根,
故原方程无解.

(2)原式=0.25×class="stub"1
4
×16-1=1-1=0.

(3)(class="stub"x+1
x-1
+class="stub"1
x2-2x+1
)÷class="stub"x
x-1

=[class="stub"x+1
x-1
+class="stub"1
(x-1)2
]•class="stub"x-1
x

=class="stub"x+1
x
+class="stub"1
x(x-1)

=
x2-1
x(x-1)
+class="stub"1
x(x-1)

=class="stub"x
x-1

取x=2,得原式=2.

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