4x2y-[6xy-2(3xy-2)-x2y]+1,其中x=-12,y=4.-数学

题目简介

4x2y-[6xy-2(3xy-2)-x2y]+1,其中x=-12,y=4.-数学

题目详情

4x2y-[6xy-2(3xy-2)-x2y]+1,其中x=-
1
2
,y=4.
题型:解答题难度:中档来源:不详

答案

4x2y-[6xy-2(3xy-2)-x2y]+1
=4x2y-[6xy-(6xy-4)-x2y]+1
=4x2y-(6xy-6xy+4-x2y)+1
=4x2y-(4-x2y)+1
=4x2y-4+x2y+1
=5x2y-3,
当x=-class="stub"1
2
,y=4时,原式=5x2y-3=5×(-class="stub"1
2
)
2
×4-3=5-3=2.

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