(1)计算:2-1+(2008-π)0-2•sin45°.(2)解方程:2x-1=x-31-x-12.-数学

题目简介

(1)计算:2-1+(2008-π)0-2•sin45°.(2)解方程:2x-1=x-31-x-12.-数学

题目详情

(1)计算:2-1+(2008-π)0-
2
•sin45°

(2)解方程:
2
x-1
=
x-3
1-x
-12
题型:解答题难度:中档来源:不详

答案

(1)2-1+(2008-π)0-
2
•sin45°

=class="stub"1
2
+1-
2
×
2
2

=class="stub"1
2

(2)class="stub"2
x-1
=class="stub"x-3
1-x
-12

方程的两边同乘(x-1),
得2=3-x-12(x-1),
解得,x=1.
检验:把x=-1代入(x-1)=0.
所以原方程无解.

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