(1)计算:(2-3)0+|-3|-2-1-2sin30°(2)解方程:xx-2-1=1x2-4.-数学

题目简介

(1)计算:(2-3)0+|-3|-2-1-2sin30°(2)解方程:xx-2-1=1x2-4.-数学

题目详情

(1)计算:(
2
-
3
)0+|-3|-2-1
-2sin30°
(2)解方程:
x
x-2
-1=
1
x2-4
题型:解答题难度:中档来源:不详

答案

(1)(
2
-
3
)0+|-3|-2-1
-2sin30°
=1+3-class="stub"1
2
-2×class="stub"1
2

=1+3-class="stub"1
2
-1
=class="stub"5
2


(2)方程两边同乘以(x+2)(x-2)得:x(x+2)-(x+2)(x-2)=1,
解得:x=-class="stub"3
2

检验:当x=-class="stub"3
2
时,(x+2)(x-2)=-class="stub"7
4
≠0,即x=-class="stub"3
2
是原分式方程的解,
故原方程的解为:x=-class="stub"3
2

更多内容推荐