计算(1)2x+1-1x-1(2)0.25×(-2)-2÷(16)-1-(π-3)0(3)a-1a+2•a2-4a2-2a+1÷1a2-1.-数学

题目简介

计算(1)2x+1-1x-1(2)0.25×(-2)-2÷(16)-1-(π-3)0(3)a-1a+2•a2-4a2-2a+1÷1a2-1.-数学

题目详情

计算
(1)
2
x+1
-
1
x-1

(2)0.25×(-2)-2÷(16)-1-(π-3)0
(3)
a-1
a+2
a2-4
a2-2a+1
÷
1
a2-1
题型:解答题难度:中档来源:不详

答案

(1)class="stub"2
x+1
-class="stub"1
x-1
=
2(x-1)
(x+1)(x-1)
-class="stub"x+1
(x+1)(x-1)
=class="stub"x-3
(x+1)(x-1)

(2)0.25×(-2)-2÷(16)-1-(π-3)0=class="stub"1
4
×class="stub"1
4
÷class="stub"1
16
-1=class="stub"1
16
×16-1=0;
(3)class="stub"a-1
a+2
a2-4
a2-2a+1
÷class="stub"1
a2-1
=class="stub"a-1
a+2
(a+2)(a-2)
(a-1)2
×(a+1)(a-1)=(a-2)(a+1)=a2-a-2.

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