(1)计算:2sin30°+23tan60°-2-1(2)解方程:12x2+12x=0.-数学

题目简介

(1)计算:2sin30°+23tan60°-2-1(2)解方程:12x2+12x=0.-数学

题目详情

(1)计算:2sin30°+2
3
tan60°-2-1

(2)解方程:
1
2
x2+
1
2
x=0
题型:解答题难度:中档来源:不详

答案

(1)原式=2×class="stub"1
2
+2
3
×
3
-class="stub"1
2

=1+6-class="stub"1
2

=6class="stub"1
2


(2)分解因式得:class="stub"1
2
x(x+1)=0,
class="stub"1
2
x=0,x+1=0,
x1=0,x2=-1.

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