用递等式计算下面各题.(125+13×24)×5(98-121÷11)÷2921×(230-192÷4)(470+35×3)÷232600÷(1280-15×72)3774÷37×(65+35)-数学

题目简介

用递等式计算下面各题.(125+13×24)×5(98-121÷11)÷2921×(230-192÷4)(470+35×3)÷232600÷(1280-15×72)3774÷37×(65+35)-数学

题目详情

用递等式计算下面各题.
(125+13×24)×5
(98-121÷11)÷2921×(230-192÷4)
(470+35×3)÷23 2600÷(1280-15×72)3774÷37×(65+35)
题型:解答题难度:中档来源:不详

答案

(125+13×24)×5
=(125+312)×5,
=437×5,
=2185;

(98-121÷11)÷29
=(98-11)÷29,
=87÷27,
=3;

21×(230-192÷4)
=21×(230-68),
=21×162,
=3402;

(470+35×3)÷23
=(470+105)÷23,
=575÷23,
=25;

2600÷(1280-15×72)
=2600÷(1280-1080),
=2600÷200,
=13;

3774÷37×(65+35)
=102×100,
=10200.

更多内容推荐