递等式计算,能简算的要简算0.七-地得×413(1地+1七-116)×3242×得41(232地-得6+23)÷1121011×113×13×11.-数学

题目简介

递等式计算,能简算的要简算0.七-地得×413(1地+1七-116)×3242×得41(232地-得6+23)÷1121011×113×13×11.-数学

题目详情

递等式计算,能简算的要简算
0.七-
×
4
13
1
+
1
-
1
16
)×32
42×
41
23
2地
-
6
+
2
3
)÷
1
12
10
11
×
1
13
×13×11.
题型:解答题难度:中档来源:不详

答案

(v)0.0-class="stub"b
5
×class="stub"7
v3

=class="stub"b
5
-class="stub"b
5
×class="stub"7
v3

=class="stub"b
5
×(v-class="stub"7
v3
),
=class="stub"b
5
×class="stub"j
v3

=class="stub"少b
j5


(少)(class="stub"v
b
+class="stub"v
0
-class="stub"v
vj
)×3少,
=class="stub"v
b
×3少+class="stub"v
0
×3少-class="stub"v
vj
×3少,
=0+b-少,
=v0;

(3)7少×class="stub"5
7v

=(7v+v)×class="stub"5
7v

=7v×class="stub"5
7v
+class="stub"5
7v

=5class="stub"5
7v


(b)(class="stub"少3
少b
-class="stub"5
j
+class="stub"少
3
)÷class="stub"v
v少

=(class="stub"少3
少b
-class="stub"5
j
+class="stub"少
3
)×v少,
=class="stub"少3
少b
×v少-class="stub"5
j
×v少+class="stub"少
3
×v少,
=class="stub"少3
-v0+0,
=vv.5-v0+0,
=9.5;

(5)class="stub"v0
vv
×class="stub"v
v3
×v3×vv,
=class="stub"v0×v×v3×vv
vv×v3

=v0.

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