用递等式计算:(1)2108+540÷18×24(2)(13+212)÷(2+323)(3)47×[0.75-(716-0.25)](4)[118+(0.65+720)÷17]×4.8.-数学

题目简介

用递等式计算:(1)2108+540÷18×24(2)(13+212)÷(2+323)(3)47×[0.75-(716-0.25)](4)[118+(0.65+720)÷17]×4.8.-数学

题目详情

用递等式计算:
(1)2108+540÷18×24
(2)(
1
3
+2
1
2
)÷(2+3
2
3

(3)
4
7
×[0.75-(
7
16
-0.25)]

(4)[1
1
8
+(0.65+
7
20
1
7
]×4.8.
题型:解答题难度:中档来源:不详

答案

(1)2108+540÷18×24,
=2108+30×24,
=2108+720,
=2828;

(2)(class="stub"1
3
+2class="stub"1
2
)÷(2+3class="stub"2
3
),
=2class="stub"5
6
÷5class="stub"2
3

=class="stub"1
2


(3)class="stub"4
7
×[0.75-(class="stub"7
16
-0.25)]

=class="stub"4
7
×[0.75-class="stub"3
16
],
=class="stub"4
7
×class="stub"9
16

=class="stub"9
28


(4)[1class="stub"1
8
+(0.65+class="stub"7
20
)÷class="stub"1
7
]×4.8,
=[1class="stub"1
8
+1÷class="stub"1
7
]×4.8,
=[1class="stub"1
8
+7]×4.8,
=8class="stub"1
8
×4.8,
=39.

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