(1)计算:①12-sin60°+(1-tan60°)-1;②a2-2a+1a-1-(a-2).(2)解方程:①2x=3x+3;②x2-3x+2=0.-数学

题目简介

(1)计算:①12-sin60°+(1-tan60°)-1;②a2-2a+1a-1-(a-2).(2)解方程:①2x=3x+3;②x2-3x+2=0.-数学

题目详情

(1)计算:①
12
-sin60°+(1-tan60°)-1;②
a2-2a+1
a-1
-(a-2).
(2)解方程:①
2
x
=
3
x+3
;②x2-3x+2=0.
题型:解答题难度:中档来源:不详

答案

(1)①
12
-sin60°+(1-tan60°)-1
=2
3
-
3
2
+class="stub"1
1-
3

=2
3
-
3
2
-
1+
3
2

=
3
-class="stub"1
2

a2-2a+1
a-1
-(a-2)
=a-1-a+2
=1
(2)①class="stub"2
x
=class="stub"3
x+3

2(x+3)=3x
x=6
经检验x=6是原方程的根.
②x2-3x+2=0.
(x-2)(x-1)=0
x1=1,x2=2.

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