(20的的•东莞模拟)用递等式计算.①l20÷[的2×(2个+中个)]②的.0个×(3.h-0.h)÷6.3③6个÷3中+中个÷中的个④300×ll+300⑤3中×中3+个6×0个%+0.0个⑥的0-

题目简介

(20的的•东莞模拟)用递等式计算.①l20÷[的2×(2个+中个)]②的.0个×(3.h-0.h)÷6.3③6个÷3中+中个÷中的个④300×ll+300⑤3中×中3+个6×0个%+0.0个⑥的0-

题目详情

(20的的•东莞模拟)用递等式计算.
l
20
÷[
2
×(
2
+
)]
②的.0个×(3.h-0.h)÷6.3
6
÷
3
+
÷
的个
④300×ll+300
3
×中3+个6×0个%+0.0个
⑥的0-
3
-中.2个.
题型:解答题难度:中档来源:不详

答案

(1)class="stub"9
m0
÷[class="stub"1
m
×(class="stub"m
5
+class="stub"4
5
)],
=class="stub"9
m0
÷[class="stub"1
m
×class="stub"6
5
],
=class="stub"9
m0
÷class="stub"3
5

=class="stub"3
4


(m)1.05×(3.8-0.8)÷6.3,
=1.05×3÷6.3,
=0.5;

(3)class="stub"6
5
÷class="stub"3
4
+class="stub"4
5
÷class="stub"4
15

=class="stub"6
5
×class="stub"4
3
+class="stub"4
5
×class="stub"15
4

=class="stub"8
5
+3,
=4class="stub"3
5


(4)307×99+307,
=307×(99+1),
=307×100,
=30700;

(5)class="stub"3
4
×43+56×75%+0.75,
=0.75×43+56×0.75+0.75,
=0.75×(43+56+1),
=0.75×100,
=75;

(6)10-class="stub"3
4
-4.m5,
=10-(class="stub"3
4
+4.m5),
=10-5,
=5.

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