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> 计算:(1)(2)x2x4+(﹣x3)2﹣x7÷x(3)(4)5x(2x2﹣3x+4)(5)(3x+5)(3﹣2x)(6)(﹣2a﹣1)2(7)(x+2)(y+3)﹣(x+1)(y﹣2)(8)(﹣2p
计算:(1)(2)x2x4+(﹣x3)2﹣x7÷x(3)(4)5x(2x2﹣3x+4)(5)(3x+5)(3﹣2x)(6)(﹣2a﹣1)2(7)(x+2)(y+3)﹣(x+1)(y﹣2)(8)(﹣2p
题目简介
计算:(1)(2)x2x4+(﹣x3)2﹣x7÷x(3)(4)5x(2x2﹣3x+4)(5)(3x+5)(3﹣2x)(6)(﹣2a﹣1)2(7)(x+2)(y+3)﹣(x+1)(y﹣2)(8)(﹣2p
题目详情
计算:(1)
(2)x
2
x
4
+(﹣x
3
)
2
﹣x
7
÷x
(3)
(4)5x(2x
2
﹣3x+4)
(5)(3x+5)(3﹣2x)
(6)(﹣2a﹣1)
2
(7)(x+2)(y+3)﹣(x+1)(y﹣2)
(8)(﹣2p﹣q+1)(﹣q+2p﹣1)
(9)(x﹣y)
2
﹣(x+y)(x﹣y)
(10)[(x+y)
2
﹣(x﹣y)
2
]÷(2xy)
题型:计算题
难度:中档
来源:河北省期中题
答案
解:(1)(﹣
)0+52+(﹣
)﹣2+(﹣2)3
=1+25+4+(﹣8)
=30﹣8
=22;
(2)x2
x4+(﹣x3)2﹣x7÷x=x6+x6﹣x6=x6;
(3)(
xy)2
(﹣12x2y2)÷(﹣
x3y)
=
x2y2
(﹣12x2y2)
(﹣
)
=4xy3;
(4)5x(2x2﹣3x+4)
=10x3﹣15x2+20x;
(5)(3x+5)(3﹣2x)
=9x﹣6x2+15﹣10x
=﹣6x2﹣x+15;
(6)(﹣2a﹣1)2
=(2a+1)2
=4a2+4a+1;
(7)(x+2)(y+3)﹣(x+1)(y﹣2)
=xy+3x+2y+6﹣(xy﹣2x+y﹣2)
=xy+3x+2y+6﹣xy+2x﹣y+2
=5x+y+8;
(8)(﹣2p﹣q+1)(﹣q+2p﹣1)
=[﹣q﹣(2p﹣1)][﹣q+(2p﹣1)]
=(﹣q)2﹣(2p﹣1)2=q2﹣(4p2﹣4p+1)
=q2﹣4p2+4p﹣1;
(9)(x﹣y)2﹣(x+y)(x﹣y)
=(x2﹣2xy+y2)﹣(x2﹣y2)
=x2﹣2xy+y2﹣x2+y2
=2y2﹣2xy;
(10)[(x+y)2﹣(x﹣y)2]÷(2xy)
=[(x2+2xy+y2)﹣(x2﹣2xy+y2)]÷2xy
=4xy÷2xy
=2.
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题目简介
计算:(1)(2)x2x4+(﹣x3)2﹣x7÷x(3)(4)5x(2x2﹣3x+4)(5)(3x+5)(3﹣2x)(6)(﹣2a﹣1)2(7)(x+2)(y+3)﹣(x+1)(y﹣2)(8)(﹣2p
题目详情
(2)x2
(3)
(4)5x(2x2﹣3x+4)
(5)(3x+5)(3﹣2x)
(6)(﹣2a﹣1)2
(7)(x+2)(y+3)﹣(x+1)(y﹣2)
(8)(﹣2p﹣q+1)(﹣q+2p﹣1)
(9)(x﹣y)2﹣(x+y)(x﹣y)
(10)[(x+y)2﹣(x﹣y)2]÷(2xy)
答案
=1+25+4+(﹣8)
=30﹣8
=22;
(2)x2
(3)(
=
=4xy3;
(4)5x(2x2﹣3x+4)
=10x3﹣15x2+20x;
(5)(3x+5)(3﹣2x)
=9x﹣6x2+15﹣10x
=﹣6x2﹣x+15;
(6)(﹣2a﹣1)2
=(2a+1)2
=4a2+4a+1;
(7)(x+2)(y+3)﹣(x+1)(y﹣2)
=xy+3x+2y+6﹣(xy﹣2x+y﹣2)
=xy+3x+2y+6﹣xy+2x﹣y+2
=5x+y+8;
(8)(﹣2p﹣q+1)(﹣q+2p﹣1)
=[﹣q﹣(2p﹣1)][﹣q+(2p﹣1)]
=(﹣q)2﹣(2p﹣1)2=q2﹣(4p2﹣4p+1)
=q2﹣4p2+4p﹣1;
(9)(x﹣y)2﹣(x+y)(x﹣y)
=(x2﹣2xy+y2)﹣(x2﹣y2)
=x2﹣2xy+y2﹣x2+y2
=2y2﹣2xy;
(10)[(x+y)2﹣(x﹣y)2]÷(2xy)
=[(x2+2xy+y2)﹣(x2﹣2xy+y2)]÷2xy
=4xy÷2xy
=2.