(1)计算:(-2)0-(13)-1-|-3|+2sin60°;(2)先化简,再求值:已知x=2+1,求(x+1x2-x-xx2-2x+1)÷1x的值.-数学

题目简介

(1)计算:(-2)0-(13)-1-|-3|+2sin60°;(2)先化简,再求值:已知x=2+1,求(x+1x2-x-xx2-2x+1)÷1x的值.-数学

题目详情

(1)计算:(-
2
)0-(
1
3
)-1-|-
3
|+2sin60°

(2)先化简,再求值:已知x=
2
+1,求(
x+1
x2-x
-
x
x2-2x+1
)÷
1
x
的值.
题型:解答题难度:中档来源:不详

答案

(1)原式=1-3-
3
+2×
3
2

=1-3-
3
+
3

=-2;

(2)原式=[class="stub"x+1
x(x-1)
-class="stub"x
(x-1)2
]•x
=
x2-1-x2
x(x-1)2
•x
=-class="stub"1
(x-1)2

当x=
2
+1时,原式=-class="stub"1
(
2
+1-1)2
=-class="stub"1
2

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