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> 计算:(1)x2x-1-x-1(2)4+(-2008)0-(13)-1+|-2|(3)(2ab2c-3)-2÷(a-2b)3(4)x2-y2x÷(x-2xy-y2x)(5)6x2-9+1x+3.-数学
计算:(1)x2x-1-x-1(2)4+(-2008)0-(13)-1+|-2|(3)(2ab2c-3)-2÷(a-2b)3(4)x2-y2x÷(x-2xy-y2x)(5)6x2-9+1x+3.-数学
题目简介
计算:(1)x2x-1-x-1(2)4+(-2008)0-(13)-1+|-2|(3)(2ab2c-3)-2÷(a-2b)3(4)x2-y2x÷(x-2xy-y2x)(5)6x2-9+1x+3.-数学
题目详情
计算:
(1)
x
2
x-1
-x-1
(2)
4
+(-2008
)
0
-(
1
3
)
-1
+|-2|
(3)(2ab
2
c
-3
)
-2
÷(a
-2
b)
3
(4)
x
2
-
y
2
x
÷(x-
2xy-
y
2
x
)
(5)
6
x
2
-9
+
1
x+3
.
题型:解答题
难度:中档
来源:不详
答案
(1)原式=
x
2
x-1
-
class="stub"x+1
1
=
x
2
x-1
-
(x+1)(x-1)
x-1
=
x
2
-(
x
2
-1)
x-1
=
class="stub"1
x-1
;
(2)原式=2+1+3+2=8;
(3)原式(2ab2c-3)-2•(a-2b)-3
=
class="stub"1
4
a-2 b-4c6•a6b-3
=
class="stub"1
4
a4b-7c6
=
a
4
c
6
4
b
7
;
(4)原式=
(x+y)(x-y)
x
÷
x
2
-2xy+
y
2
x
=
(x+y)(x-y)
x
•
class="stub"x
(x-y
)
2
=
class="stub"x+y
x-y
;
(5)原式=
class="stub"6
(x+3)(x-3)
+
class="stub"x-3
(x+3)(x-3)
=
class="stub"x+3
(x+3)(x-3)
=
class="stub"1
x-3
.
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题目简介
计算:(1)x2x-1-x-1(2)4+(-2008)0-(13)-1+|-2|(3)(2ab2c-3)-2÷(a-2b)3(4)x2-y2x÷(x-2xy-y2x)(5)6x2-9+1x+3.-数学
题目详情
(1)
(2)
(3)(2ab2c-3)-2÷(a-2b)3
(4)
(5)
答案
=
=
=
(2)原式=2+1+3+2=8;
(3)原式(2ab2c-3)-2•(a-2b)-3
=
=
=
(4)原式=
=
=
(5)原式=
=
=