计算:(1)x2x-1-x-1(2)4+(-2008)0-(13)-1+|-2|(3)(2ab2c-3)-2÷(a-2b)3(4)x2-y2x÷(x-2xy-y2x)(5)6x2-9+1x+3.-数学

题目简介

计算:(1)x2x-1-x-1(2)4+(-2008)0-(13)-1+|-2|(3)(2ab2c-3)-2÷(a-2b)3(4)x2-y2x÷(x-2xy-y2x)(5)6x2-9+1x+3.-数学

题目详情

计算:
(1)
x2
x-1
-x-1

(2)
4
+(-2008)0-(
1
3
)-1+|-2|

(3)(2ab2c-3-2÷(a-2b)3
(4)
x2-y2
x
÷(x-
2xy-y2
x
)

(5)
6
x2-9
+
1
x+3
题型:解答题难度:中档来源:不详

答案

(1)原式=
x2
x-1
-class="stub"x+1
1

=
x2
x-1
-
(x+1)(x-1)
x-1

=
x2-(x2-1)
x-1

=class="stub"1
x-1


(2)原式=2+1+3+2=8;

(3)原式(2ab2c-3)-2•(a-2b)-3
=class="stub"1
4
a-2 b-4c6•a6b-3
=class="stub"1
4
a4b-7c6
=
a4c6
4b7


(4)原式=
(x+y)(x-y)
x
÷
x2-2xy+y2
x

=
(x+y)(x-y)
x
class="stub"x
(x-y)2

=class="stub"x+y
x-y


(5)原式=class="stub"6
(x+3)(x-3)
+class="stub"x-3
(x+3)(x-3)

=class="stub"x+3
(x+3)(x-3)

=class="stub"1
x-3

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