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> 实验1在洁净的玻璃板的两侧,分别滴有少许土壤浸出液和等量的蒸馏水,将玻璃板放在火焰上加热,待土壤浸出液和蒸馏水完全蒸发后,观察发生了什么现象。实验2中用甲、乙两个试-七年级生物
实验1在洁净的玻璃板的两侧,分别滴有少许土壤浸出液和等量的蒸馏水,将玻璃板放在火焰上加热,待土壤浸出液和蒸馏水完全蒸发后,观察发生了什么现象。实验2中用甲、乙两个试-七年级生物
题目简介
实验1在洁净的玻璃板的两侧,分别滴有少许土壤浸出液和等量的蒸馏水,将玻璃板放在火焰上加热,待土壤浸出液和蒸馏水完全蒸发后,观察发生了什么现象。实验2中用甲、乙两个试-七年级生物
题目详情
实验1在洁净的玻璃板的两侧,分别滴有少许土壤浸出液和等量的蒸馏水,将玻璃板放在火焰上加热,待土壤浸出液和蒸馏水完全蒸发后,观察发生了什么现象。实验2中用甲、乙两个试管(甲中为土壤浸出液,乙中为蒸馏水)各培养一株大小相同的健壮幼苗,两周以后,观察这两棵幼苗,其生长状况如图所示,请你分析两个实验,回答以下问题:
(1)实验1中,现象是土壤浸出液残留有少量灰白色物质,证明里面含有
。而蒸馏水
,证明里面不含
。
(2)从实验2可以看出,幼苗生长状况较好的是
,与实验1合起来分析,你可以得到什么结论?
。
题型:读图填空题
难度:中档
来源:同步题
答案
(1)无机盐;没有残留物;无机盐
(2)甲;植物的生活需要无机盐,缺少无机盐,植物不能正常生长
上一篇 :
_____ is necessary for us to
下一篇 :
下图表示植物细胞吸水和失水示
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题目简介
实验1在洁净的玻璃板的两侧,分别滴有少许土壤浸出液和等量的蒸馏水,将玻璃板放在火焰上加热,待土壤浸出液和蒸馏水完全蒸发后,观察发生了什么现象。实验2中用甲、乙两个试-七年级生物
题目详情
(2)从实验2可以看出,幼苗生长状况较好的是 ,与实验1合起来分析,你可以得到什么结论? 。
答案
(2)甲;植物的生活需要无机盐,缺少无机盐,植物不能正常生长