计算和解方程(1)130-(-23-35)÷(-2)(2)(-23)×278÷(32)2(3)4x-3(20-x)=-4(4)x-74-5x+83=1.-数学

题目简介

计算和解方程(1)130-(-23-35)÷(-2)(2)(-23)×278÷(32)2(3)4x-3(20-x)=-4(4)x-74-5x+83=1.-数学

题目详情

计算和解方程
(1)
1
30
-(-
2
3
-
3
5
)÷(-2)

(2)(-
2
3
27
8
÷(
3
2
)2

(3)4x-3(20-x)=-4
(4)
x-7
4
-
5x+8
3
=1
题型:解答题难度:中档来源:不详

答案

(1)class="stub"1
30
-(-class="stub"2
3
-class="stub"3
5
)÷(-2)
=class="stub"1
30
-(-class="stub"19
15
)×(-class="stub"1
2

=class="stub"1
30
-class="stub"19
30

=-class="stub"3
5


(2)(-class="stub"2
3
)×class="stub"27
8
÷(class="stub"3
2
)2
=(-class="stub"2
3
)×class="stub"27
8
×class="stub"4
9

=-1;

(3)去括号得,4x-60+3x=-4,
移项得,4x+3x=-4+60,
合并同类项得,7x=56,
系数化为1得,x=8;

(4)去分母得,3(x-7)-4(5x+8)=12,
去括号得,3x-21-20x-32=12,
移项得,3x-20x=12+21+32,
合并同类项得,-17x=65,
系数化为1得,x=-class="stub"65
17

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