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> (1)计算①(-13)-2-16÷(-2)3+(π-32)0-23×3.②614+33+38+|2-3|-3-(-4)2.(2)因式分ax2-2ax+a;(3)先化简,再求值:a+1a-1-aa2-2
(1)计算①(-13)-2-16÷(-2)3+(π-32)0-23×3.②614+33+38+|2-3|-3-(-4)2.(2)因式分ax2-2ax+a;(3)先化简,再求值:a+1a-1-aa2-2
题目简介
(1)计算①(-13)-2-16÷(-2)3+(π-32)0-23×3.②614+33+38+|2-3|-3-(-4)2.(2)因式分ax2-2ax+a;(3)先化简,再求值:a+1a-1-aa2-2
题目详情
(1)计算①
(-
1
3
)
-2
-16÷(-2
)
3
+(π-
3
2
)
0
-2
3
×
3
.
②
6
1
4
+
3
3+
3
8
+|
2
-
3
|-
3
-
(-4)
2
.
(2)因式分ax
2
-2ax+a;
(3)先化简,再求值:
a+1
a-1
-
a
a
2
-2a+1
÷
1
a
,其中a=1-
2
.
题型:解答题
难度:中档
来源:不详
答案
(1)①原式=9-16÷(-8)+1-6=9+2+1-6=6;
②原式=
class="stub"5
2
+
class="stub"3
2
+
3
-
2
-
3
-4=-
2
;
(2)原式=a(x2-2x+1)=a(x-1)2;
(3)原式=
class="stub"a+1
a-1
-
a
2
(a-1
)
2
=
(a+1)(a-1)
(a-1
)
2
-
a
2
(a-1
)
2
=-
class="stub"1
(a-1
)
2
,
当a=1-
2
时,原式=-
class="stub"1
(1-
2
-1
)
2
=-
class="stub"1
2
.
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题目简介
(1)计算①(-13)-2-16÷(-2)3+(π-32)0-23×3.②614+33+38+|2-3|-3-(-4)2.(2)因式分ax2-2ax+a;(3)先化简,再求值:a+1a-1-aa2-2
题目详情
②
(2)因式分ax2-2ax+a;
(3)先化简,再求值:
答案
②原式=
(2)原式=a(x2-2x+1)=a(x-1)2;
(3)原式=
当a=1-