计算(1)(1100)0+(-3)2+3-1-(-3)2(2)已知x+1x=10,求x2+1x2的值(3)(x+6)2-(x-3)(x+3)2(4)[(3xy+z)2-z2]÷xy.-数学

题目简介

计算(1)(1100)0+(-3)2+3-1-(-3)2(2)已知x+1x=10,求x2+1x2的值(3)(x+6)2-(x-3)(x+3)2(4)[(3xy+z)2-z2]÷xy.-数学

题目详情

计算
(1)(
1
100
)0+(-3)2+3-1-(-3)2

(2)已知x+
1
x
=10
,求x2+
1
x2
的值
(3)(x+6)2-(x-3)(x+3)2
(4)[(3xy+z)2-z2]÷xy.
题型:解答题难度:中档来源:不详

答案

(1)原式=1+9-class="stub"1
3
-9
=class="stub"2
3


(2)∵x+class="stub"1
x
=10,
∴(x+class="stub"1
x
)2=x2+2+class="stub"1
x2
=100,
则x2+class="stub"1
x2
=98;

(3)原式=x2+12x+36-(x-3)(x2+6x+9)
=x2+12x+36-(x3-27)
=x2+12x+36-x3+27;

(4)原式=(9x2y2+6xyz+z2-z2)÷xy
=9xy+6z.

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