计算:(1)(3-2)0-(-12)2÷2-2-(-1)3(2)aa2-2a+13-a÷2-a9-a2(3)12x-1x+y(x+y2x-x-y)(4)a2a-1-a-1.-数学

题目简介

计算:(1)(3-2)0-(-12)2÷2-2-(-1)3(2)aa2-2a+13-a÷2-a9-a2(3)12x-1x+y(x+y2x-x-y)(4)a2a-1-a-1.-数学

题目详情

计算:
(1)(
3
-
2
)0-(-
1
2
)2÷2-2-(-1)3

(2)
a
a2-2a
+
1
3-a
÷
2-a
9-a2

(3)
1
2x
-
1
x+y
(
x+y
2x
-x-y)

(4)
a2
a-1
-a-1
题型:解答题难度:中档来源:不详

答案

(1)原式=1-class="stub"1
4
÷class="stub"1
4
+1,
=1-1+1,
=1.
(2)原式=class="stub"1
a -2
+class="stub"1
3-a
÷class="stub"2-a
(3+a)(3-a)

=class="stub"1
a -2
+class="stub"1
3-a
(3+a)(3-a)
(2-a)

=class="stub"1
a -2
+class="stub"3+a
(2-a)

=class="stub"1
a -2
-class="stub"3+a
a-2

=class="stub"-2-a
a-2

(3)原式=class="stub"1
2x
-(class="stub"1
2x
-1)

=class="stub"1
2x
-class="stub"1
2x
+1

=1.
(4)原式=
a2
a-1
-
a2-1
a-1

=class="stub"1
a-1

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